introductory-examples/control-structures/control-demo.cs - A Demonstration of switch.

Lecture 0 - slide 8 : 25 Program 2

  public static void SwitchDemo(){
    int j = 1;

    /* Illegal: Control cannot fall through from one case label to another
    switch (j) {
      case 0:  Console.WriteLine("j is 0");
      case 1:  Console.WriteLine("j is 1");
      case 2:  Console.WriteLine("j is 2");
      default: Console.WriteLine("j is not 0, 1 or 2");
    }   
    */

    /* Break or similar jumping is needed:  */
    switch (j) {   
      case 0:  Console.WriteLine("j is 0"); break;
      case 1:  Console.WriteLine("j is 1"); break;
      case 2:  Console.WriteLine("j is 2"); break;
      default: Console.WriteLine("j is not 0, 1 or 2"); break;
    }   

    /* Falling through empty cases is possible:  */   
    switch (j) {        
      case 0: case 1:  Console.WriteLine("j is 0 or 1"); break;
      case 2: case 3:  Console.WriteLine("j is 2 or 3"); break;
      case 4: case 5:  Console.WriteLine("j is 4 or 5"); break;
      default: Console.WriteLine("j is not 1, 2, 3, 4, or 5"); break;
    }   

    /* It is possible to switch on strings:  */
    string str = "two";
    switch (str) {
      case "zero":  Console.WriteLine("str is 0"); break;
      case "one":  Console.WriteLine("str is 1"); break;
      case "two":  Console.WriteLine("str is 2"); break;
      default: Console.WriteLine("str is not 0, 1 or 2"); break;
    }   

  }