// Illustration of implicit conversions between Point and double.
// Point(): (0,7)   Point(x): (x, 20)   Point(x,y): (x,y)    Point(p) = (p.x+1,p.y+2)    double(p) = p.x+p.y

#include <iostream>
#include <string>
#include "point1.h"

using namespace std;

int main(){
  double d1, d2;
  Point p1, p2;      // Both (0, 7), not important for 
                     // this example.

  p1 = 5.0;          // (5, 20)  - Using Point(double)
  p2 = Point(p1);    // (6, 22)  - Using copy constructor. Default assignment is used.

  cout << "p1: " << p1 << endl;    // (5, 20)
  cout << "p2: " << p2 << endl;    // (6, 22)

  d1 = p1;           // 25  - Using conversion operator double() in Point.
  d2 = p1 - p2;      // Implicitly converts both p1 and p2 to doubles: 25 and 28.
                     // Using conversion operator twice.
                     // 25 - 28 == -3, 

  cout << "d1: " << d1 << endl;  // 25
  cout << "d2: " << d2 << endl;  // -3
}